Proof that .9=1 (this is my first Ytmnd so please give constructive criticism
Created on: November 19th, 2006
Please go easy on me, because this is my first Ytmnd and I did it in Sound Recorder and Paint.
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What a f*cking waste of my goddamn time you f*got, you're probly a stupid f*cking f*g who forgot about POLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND POLANDPOLAND
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"Bertrand Russell, in a lecture on logic, mentioned that in the sense of
material implication, a false proposition implies any proposition. A
student raised his hand and said "In that case, given that 1 = 0, prove
that you are the Pope". Russell immediately replied, "Add 1 to both sides
of the equation: then we have 2 = 1. The set containing just me and the
Pope has 2 members. But 2 = 1, so it has only 1 member; therefore, I am
the Pope."
a.)Assume 1=.9. b.)Let x=.9 Then 10x-x=9-.9 (8.1=8.1) c.) (from a.) 1=.9 (from b.) .9=x Thus, by the transitive property, x=1. If 1=.9, and 10x-x=9-.9 when x=.9, then 10x-x=9-.9 when x=1 (10-1=9-.9... 9=8.1). Since this is an outright contradiction, the assumption is false. (Any assumption that leads to a contradiction implies a false assumption).
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